A Math Principle

November 24

任意一个凸四边形都有：

(AC+BD)^2<=(AB+CD)^2+(BC+DA)^2

等号成立条件为ABCD为矩形。

一个矩形像个0，两条对角线像个斜着的+号

+0。小小的数学课上的发现，本人命名它为Galin不等式……

仅以此怀念过去……

6:01 PM | Blog it

To add a comment, sign in with your Windows Live ID (if you use Hotmail, Messenger, or Xbox LIVE, you have a Windows Live ID). Sign in

Don't have a Windows Live ID? Sign up

Taliawrote:

倒。你的想像力超级丰富。。。

佩服的。

Nov. 24

The trackback URL for this entry is:

http://jerryzhou216.spaces.live.com/blog/cns!A82CDEC108579498!855.trak

Weblogs that reference this entry